en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=82x^4+41x

Solution

extreme points

f (x) = 82 x^{4} + 41 x

Solution

Minimum (- \frac{1}{2}, - \frac{123}{8})

Solution steps

f^{'} (x) = 328 x^{3} + 41

Find intervals:

Decreasing

: - \infty < x < - \frac{1}{2},

Increasing

: - \frac{1}{2} < x < \infty

Plug

x = - \frac{1}{2}

into

82 x^{4} + 41 x : - \frac{123}{8}

Minimum (- \frac{1}{2}, - \frac{123}{8})

Popular Examples

domain of f(x)=(x+2)/(x^2-9)domain

f (x) = \frac{x + 2}{x ^{2} - 9}

critical f(x)=(x-1)^{4/3}critical points

f (x) = (x - 1)^{\frac{4}{3}}

slope of 3x-3 slope

3 x - 3

slope of 2x+7y+6=0 slope

2 x + 7 y + 6 = 0

domain of f(x)=x-6 domain

f (x) = x - 6

Frequently Asked Questions (FAQ)

What is the extreme f(x)=82x^4+41x ?
The extreme f(x)=82x^4+41x is Minimum(-1/2 ,-123/8)