What is the domain of y=sqrt(36-x^2) ?

The domain of y=sqrt(36-x^2) is -6<= x<= 6

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domain of y=sqrt(36-x^2)

domain

y = 36 - x^{2}

- 6 \leq x \leq 6

Interval Notation

[- 6, 6]

Solution steps

Find non-negative values for radicals:

- 6 \leq x \leq 6

The function domain

- 6 \leq x \leq 6

f (x) = 81 - \frac{2}{x}

f (x) = \frac{3 x - 3}{x + 2}

f (x) = x^{2} + 7 x + 10

f (x) = \frac{1}{x} + 5

f (x) = 5 x ∣ x ∣

What is the domain of y=sqrt(36-x^2) ?
The domain of y=sqrt(36-x^2) is -6<= x<= 6