What is the domain of f(x)=((x+1))/((2x+1)) ?

The domain of f(x)=((x+1))/((2x+1)) is x -1/2

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domain of f(x)=((x+1))/((2x+1))

domain

f (x) = \frac{( x + 1 )}{( 2 x + 1 )}

x < - \frac{1}{2} or x > - \frac{1}{2}

Interval Notation

(- \infty, - \frac{1}{2}) \cup (- \frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{1}{2}

The function domain

x < - \frac{1}{2} or x > - \frac{1}{2}

(- 1.2) (- 9.4)

f (x) = \frac{x}{x ^{2} - 16}

f (x) = \frac{7}{x ^{8} + 5 x + 1}

(10, - 1), (- 4, - 5)

f (x) = \frac{1}{( x - 7 ) ^{2}}

What is the domain of f(x)=((x+1))/((2x+1)) ?
The domain of f(x)=((x+1))/((2x+1)) is x<-1/2 \lor x>-1/2