What is the domain of f(x)=(3/2)/(2sqrt(5/2+3/2 x)) ?

The domain of f(x)=(3/2)/(2sqrt(5/2+3/2 x)) is x>-5/3

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domain of f(x)=(3/2)/(2sqrt(5/2+3/2 x))

domain

f (x) = \frac{\frac{3}{2}}{2 \frac{5}{2} + \frac{3}{2} x}

x > - \frac{5}{3}

Interval Notation

(- \frac{5}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{5}{3}

Find undefined (singularity) points:

x = - \frac{5}{3}

Combine real regions and undefined points for final function domain

x > - \frac{5}{3}

x - 5

f (x) = - \frac{x ^{2}}{2} - 3 x - \frac{1}{2}

y = \frac{2 e ^{x}}{e ^{x} - 5}

f (x) = \frac{x ^{2} + 2}{x + 4}

f (x) = 8 - 4 x

What is the domain of f(x)=(3/2)/(2sqrt(5/2+3/2 x)) ?
The domain of f(x)=(3/2)/(2sqrt(5/2+3/2 x)) is x>-5/3