What is the inverse of f(x)=sqrt(64-x^2) ?

The inverse of f(x)=sqrt(64-x^2) is sqrt(-x^2+64),-sqrt(-x^2+64)

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inverse of f(x)=sqrt(64-x^2)

inverse

f (x) = 64 - x^{2}

- x^{2} + 64, - - x^{2} + 64

Solution steps

y = 64 - x^{2}

Replace

x

with

y

x = 64 - y^{2}

Solve for

y, x = 64 - y^{2}

- x^{2} + 64, - - x^{2} + 64

sin^{2} (x)

f (x) = \frac{x - 16}{x + 6}

f (x) = \frac{x - 5}{x - 2}

f (x) = x + 1

\frac{x}{1 + x ^{2}}

What is the inverse of f(x)=sqrt(64-x^2) ?
The inverse of f(x)=sqrt(64-x^2) is sqrt(-x^2+64),-sqrt(-x^2+64)