What is the inverse of f(x)=-2(x+1)^2-3 ?

The inverse of f(x)=-2(x+1)^2-3 is sqrt(-(x+3)/2)-1,-sqrt(-(x+3)/2)-1

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inverse of f(x)=-2(x+1)^2-3

inverse

f (x) = - 2 (x + 1)^{2} - 3

- \frac{x + 3}{2} - 1, - - \frac{x + 3}{2} - 1

Solution steps

y = - 2 (x + 1)^{2} - 3

Replace

x

with

y

x = - 2 (y + 1)^{2} - 3

Solve for

y, x = - 2 (y + 1)^{2} - 3

- \frac{x + 3}{2} - 1, - - \frac{x + 3}{2} - 1

y = 4 x - x^{2}

(8) (- 9) m = - \frac{5}{4}

2 x + y = - 1

f (x) = \frac{5 x}{x - 3}

- x^{2} - 6 x

What is the inverse of f(x)=-2(x+1)^2-3 ?
The inverse of f(x)=-2(x+1)^2-3 is sqrt(-(x+3)/2)-1,-sqrt(-(x+3)/2)-1