What is the domain of f(x)=(-9)/(x^2-3) ?

The domain of f(x)=(-9)/(x^2-3) is x sqrt(3)

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domain of f(x)=(-9)/(x^2-3)

domain

f (x) = \frac{- 9}{x ^{2} - 3}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

y = \frac{1}{2} x + 8

f (x) = \frac{x + 7}{x ^{2} - 49}

2 cos (3 x)

f (x) = x^{4} - 5

x = - 8

What is the domain of f(x)=(-9)/(x^2-3) ?
The domain of f(x)=(-9)/(x^2-3) is x<-sqrt(3)\lor-sqrt(3)<x<sqrt(3)\lor x>sqrt(3)