What is the perpendicular y=-7x,(35,12) ?

The perpendicular y=-7x,(35,12) is y= 1/7 x+7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

perpendicular y=-7x,(35,12)

perpendicular

y = - 7 x, (35, 12)

y = \frac{1}{7} x + 7

Solution steps

Find the line

y = mx + b

perpendicular to

y = - 7 x

that passes through

(35, 12)

Find the slope of

y = - 7 x : m = - 7

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{7}

Find the line with slope m=

\frac{1}{7}

and passing through

(35, 12) : y = \frac{1}{7} x + 7

y = \frac{1}{7} x + 7

f (x) = \frac{x}{x ^{2}}

sin (θ)

y = \frac{1}{8} tan (x)

\frac{14 x + 48}{x ( x + 8 )}

f (x) = 6 x - x^{2}, x < 4

What is the perpendicular y=-7x,(35,12) ?
The perpendicular y=-7x,(35,12) is y= 1/7 x+7