What is the domain of f(x)=(sqrt(x+2))/(x^2-2x-8) ?

The domain of f(x)=(sqrt(x+2))/(x^2-2x-8) is -2 4

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domain of f(x)=(sqrt(x+2))/(x^2-2x-8)

domain

f (x) = \frac{x + 2}{x ^{2} - 2 x - 8}

- 2 < x < 4 or x > 4

Interval Notation

(- 2, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = 4, x = - 2

Combine real regions and undefined points for final function domain

- 2 < x < 4 or x > 4

f (x) = - x^{3} - 3 x^{2} - 1

y = - \frac{5}{2} x + 4

8 x + 6 y = - 4

13 = 0 \cdot 16 + b

y = x^{2} + 4

What is the domain of f(x)=(sqrt(x+2))/(x^2-2x-8) ?
The domain of f(x)=(sqrt(x+2))/(x^2-2x-8) is -2<x<4\lor x>4