What is the inverse of sqrt(4-y^2)+1 ?

The inverse of sqrt(4-y^2)+1 is sqrt(-y^2+2y+3),-sqrt(-y^2+2y+3)

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inverse of sqrt(4-y^2)+1

inverse

4 - y^{2} + 1

- y^{2} + 2 y + 3, - - y^{2} + 2 y + 3

Solution steps

y = 4 - y^{2} + 1

Replace

y

with

y

y = 4 - y^{2} + 1

Solve for

y, y = 4 - y^{2} + 1

- y^{2} + 2 y + 3, - - y^{2} + 2 y + 3

\frac{2 e ^{x}}{e ^{x} - 5}

f (x) = \frac{4}{4 + x}

f (x) = 7 ln (x)

f (x) = \frac{x}{x + 1}

y = \frac{1}{2} x + 3

What is the inverse of sqrt(4-y^2)+1 ?
The inverse of sqrt(4-y^2)+1 is sqrt(-y^2+2y+3),-sqrt(-y^2+2y+3)