What is the range of f(x)=2cos(3x) ?

The range of f(x)=2cos(3x) is -2<= f(x)<= 2

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range of f(x)=2cos(3x)

range

f (x) = 2 cos (3 x)

- 2 \leq f (x) \leq 2

Interval Notation

[- 2, 2]

Solution steps

The range of the basic

cos

function is

- 1 \leq cos (3 x) \leq 1

- 1 \leq cos (3 x) \leq 1

Multiply the edges of the range by:

2

- 2 \leq 2 cos (3 x) \leq 2

Therefore the range is

- 2 \leq f (x) \leq 2

\frac{x}{9 - x ^{2}}

y = 4 x + 2

(x + 5)^{2} - 4

y = \frac{4}{3} x - 2

2 x - 3 y = 8

What is the range of f(x)=2cos(3x) ?
The range of f(x)=2cos(3x) is -2<= f(x)<= 2