What is the range of f(x)=sqrt(3x-1) ?

The range of f(x)=sqrt(3x-1) is f(x)>= 0

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range of f(x)=sqrt(3x-1)

range

f (x) = 3 x - 1

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 0

f (x) \geq 0

f (x) = ln (6 x^{2} - 6 x - 11)

y = \frac{1}{3} x - 1

\frac{x}{x ^{2} + 12 x + 32}

5 x + 6 y = 7

\frac{x ^{2} - 1}{x - 1}