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Popular >

distance (-2,-4),(3,-7)

Solution

distance

(- 2, - 4), (3, - 7)

Solution

34

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 2, - 4)

and

(3, - 7)

is

= (3 - (- 2))^{2} + (- 7 - (- 4))^{2}

Simplify

= 34

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extreme 2x^2-1/(x^2)extreme points

2 x^{2} - \frac{1}{x ^{2}}

range of (6x)/(x+5)range

\frac{6 x}{x + 5}

inverse of f(x)=80+x inverse

f (x) = 80 + x

midpoint (2,-3),(-2,5)midpoint

(2, - 3), (- 2, 5)

critical 8-3x-2x^2 critical points

8 - 3 x - 2 x^{2}

Frequently Asked Questions (FAQ)

What is the distance (-2,-4),(3,-7) ?
The distance (-2,-4),(3,-7) is square root of 34