What is the inverse of f(x)=x^2-3x+3 ?

The inverse of f(x)=x^2-3x+3 is (3+sqrt(4x-3))/2 ,(3-sqrt(4x-3))/2

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inverse of f(x)=x^2-3x+3

inverse

f (x) = x^{2} - 3 x + 3

\frac{3 + 4 x - 3}{2}, \frac{3 - 4 x - 3}{2}

Solution steps

y = x^{2} - 3 x + 3

Replace

x

with

y

x = y^{2} - 3 y + 3

Solve for

y, x = y^{2} - 3 y + 3

\frac{3 + 4 x - 3}{2}, \frac{3 - 4 x - 3}{2}

f (x) = x^{3} - 8 x^{2} + 9 x + 18 = 0

f (x) = \frac{x ^{2} - 1}{x}

f (x) = \frac{x - 1}{( x + 3 ) ( x - 2 )}

f (x) = \frac{2}{x - 6}

x 4 - x

What is the inverse of f(x)=x^2-3x+3 ?
The inverse of f(x)=x^2-3x+3 is (3+sqrt(4x-3))/2 ,(3-sqrt(4x-3))/2