en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)=x^2+x-2

Solution

range

f (x) = x^{2} + x - 2

Solution

f (x) \geq - \frac{9}{4}

+1

Interval Notation

[- \frac{9}{4}, \infty)

Solution steps

Vertex of

x^{2} + x - 2 :

Minimum

(- \frac{1}{2}, - \frac{9}{4})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- \frac{1}{2}, - \frac{9}{4})

f (x) \geq - \frac{9}{4}

Popular Examples

parity f(x)=x^3-x^2+4x+2 parity

f (x) = x^{3} - x^{2} + 4 x + 2

range of (x+2)/6 range

\frac{x + 2}{6}

extreme f(x)=sin(x)extreme points

f (x) = sin (x)

inverse of (10(x-4))/3 inverse

\frac{10 ( x - 4 )}{3}

domain of f(x)= 3/(x^2+4)domain

f (x) = \frac{3}{x ^{2} + 4}

Frequently Asked Questions (FAQ)

What is the range of f(x)=x^2+x-2 ?
The range of f(x)=x^2+x-2 is f(x)>=-9/4