What is the inverse of (x^2-5)/(7x^2) ?

The inverse of (x^2-5)/(7x^2) is sqrt(-5/(7x-1)),-sqrt(-5/(7x-1))

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inverse of (x^2-5)/(7x^2)

inverse

\frac{x ^{2} - 5}{7 x ^{2}}

- \frac{5}{7 x - 1}, - - \frac{5}{7 x - 1}

Solution steps

y = \frac{x ^{2} - 5}{7 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 5}{7 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 5}{7 y ^{2}}

- \frac{5}{7 x - 1}, - - \frac{5}{7 x - 1}

f (x) = - 2 ln (- x + 2) + 5

f (x) = \frac{x - 3}{x ^{2} - 5 x}

y = a x + 1

(7, 1), (- 16, - 16)

f (x) = \frac{( 2 x + 1 )}{x ^{2} + x - 2}

What is the inverse of (x^2-5)/(7x^2) ?
The inverse of (x^2-5)/(7x^2) is sqrt(-5/(7x-1)),-sqrt(-5/(7x-1))