What is the domain of f(x)=(sqrt(x+8))/(x-5) ?

The domain of f(x)=(sqrt(x+8))/(x-5) is -8 5

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domain of f(x)=(sqrt(x+8))/(x-5)

domain

f (x) = \frac{x + 8}{x - 5}

- 8 \leq x < 5 or x > 5

Interval Notation

[- 8, 5) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 8

Find undefined (singularity) points:

x = 5

Combine real regions and undefined points for final function domain

- 8 \leq x < 5 or x > 5

f (x) = 6 x^{\frac{1}{4}} + 8

- \frac{x}{x - 8}

(3, - 4), (- 1, 4)

f (x) = sin (π x)

x^{4} - 2 x^{2} + 3

What is the domain of f(x)=(sqrt(x+8))/(x-5) ?
The domain of f(x)=(sqrt(x+8))/(x-5) is -8<= x<5\lor x>5