What is the inverse of f(x)=(x-3)^2-4 ?

The inverse of f(x)=(x-3)^2-4 is sqrt(x+4)+3,-sqrt(x+4)+3

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inverse of f(x)=(x-3)^2-4

inverse

f (x) = (x - 3)^{2} - 4

x + 4 + 3, - x + 4 + 3

Solution steps

y = (x - 3)^{2} - 4

Replace

x

with

y

x = (y - 3)^{2} - 4

Solve for

y, x = (y - 3)^{2} - 4

x + 4 + 3, - x + 4 + 3

f (x) = - 2 cos (3 x)

f (x) = \frac{x ^{2} + 7 x + 8}{x + 3}

f (x) = cos (\frac{23 π}{6})

6 y - 3 x = - 24

f (x) = \frac{1}{5 - x}

What is the inverse of f(x)=(x-3)^2-4 ?
The inverse of f(x)=(x-3)^2-4 is sqrt(x+4)+3,-sqrt(x+4)+3