What is the domain of 1/(\sqrt[4]{x^2-3x)} ?

The domain of 1/(\sqrt[4]{x^2-3x)} is x 3

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domain of 1/(\sqrt[4]{x^2-3x)}

domain

x < 0 or x > 3

Interval Notation

(- \infty, 0) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 3

Find undefined (singularity) points:

x = 3, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 3

\frac{x + 1}{2 x - 1}

f (x) = (x - 1)^{2} - 6

f (x) = \frac{6 x}{x + 5}

f (x) = 2 x (x + 4)^{2}

y = - 3

What is the domain of 1/(\sqrt[4]{x^2-3x)} ?
The domain of 1/(\sqrt[4]{x^2-3x)} is x<0\lor x>3