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Popular >

range of cos(2φ)

Solution

range

cos (2 φ)

Solution

- 1 \leq f (φ) \leq 1

+1

Interval Notation

[- 1, 1]

Solution steps

The range of the basic

cos

function is

- 1 \leq cos (2 φ) \leq 1

- 1 \leq cos (2 φ) \leq 1

Therefore the range is

- 1 \leq f (φ) \leq 1

Popular Examples

perpendicular y+3= 3/4 x+5 perpendicular

y + 3 = \frac{3}{4} x + 5

intercepts of f(x)=ln(x)+6 intercepts

f (x) = ln (x) + 6

range of 3/((sqrt(2x-5)))range

\frac{3}{( 2 x - 5 )}

simplify (3.5)(2.6)simplify

(3.5) (2.6)

domain of f(x)=sqrt(5-x^2)domain

f (x) = 5 - x^{2}

Frequently Asked Questions (FAQ)

What is the range of cos(2φ) ?
The range of cos(2φ) is -1<= f(φ)<= 1