What is the extreme f(x)=-16x^2+128x+340 ?

The extreme f(x)=-16x^2+128x+340 is Maximum(4,596)

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extreme f(x)=-16x^2+128x+340

extreme points

f (x) = - 16 x^{2} + 128 x + 340

Maximum (4, 596)

Solution steps

f^{'} (x) = - 32 x + 128

Find intervals:

Increasing

: - \infty < x < 4,

Decreasing

: 4 < x < \infty

Plug

x = 4

into

- 16 x^{2} + 128 x + 340 : 596

Maximum (4, 596)

\frac{3}{x - 5}

f (x) = \frac{x ^{2} + 1 + 20 x}{x ^{2} + 1 + 2 x}

f (x) = lo g_{10} (1 - x^{2})

f (x) = \frac{x}{x - 6}

f (x) = - \frac{4}{5} x + \frac{1}{5}

What is the extreme f(x)=-16x^2+128x+340 ?
The extreme f(x)=-16x^2+128x+340 is Maximum(4,596)