What is the extreme \sqrt[5]{x}(x-2) ?

The extreme \sqrt[5]{x}(x-2) is Minimum(1/3 ,-5/(3\sqrt[5]{3)})

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extreme \sqrt[5]{x}(x-2)

extreme points

Solution steps

Find the critical points:

x = 0, x = \frac{1}{3}

Domain of

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < \frac{1}{3},

Increasing

: \frac{1}{3} < x < \infty

Plug the extreme point

x = \frac{1}{3}

into

f (x) = cosh (x)

y = \frac{x}{x - 1}

y = 3 (7 x + 192)

2 - x + 4

What is the extreme \sqrt[5]{x}(x-2) ?
The extreme \sqrt[5]{x}(x-2) is Minimum(1/3 ,-5/(3\sqrt[5]{3)})