What is the inverse of (x^2-16)/(3x^2) ?

The inverse of (x^2-16)/(3x^2) is sqrt(-(16)/(3x-1)),-sqrt(-(16)/(3x-1))

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inverse of (x^2-16)/(3x^2)

inverse

\frac{x ^{2} - 16}{3 x ^{2}}

- \frac{16}{3 x - 1}, - - \frac{16}{3 x - 1}

Solution steps

y = \frac{x ^{2} - 16}{3 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 16}{3 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 16}{3 y ^{2}}

- \frac{16}{3 x - 1}, - - \frac{16}{3 x - 1}

f (x) = t 4 - t

x^{2} - 2

- x^{3} + 12 x - 16

f (x) = x^{2} - 18

f (x) = 2 csc (3 (x - \frac{π}{4}))

What is the inverse of (x^2-16)/(3x^2) ?
The inverse of (x^2-16)/(3x^2) is sqrt(-(16)/(3x-1)),-sqrt(-(16)/(3x-1))