What is the critical f(x)=x^2(x^2-4) ?

The critical f(x)=x^2(x^2-4) is x=-sqrt(2),x=0,x=sqrt(2)

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critical f(x)=x^2(x^2-4)

critical points

f (x) = x^{2} (x^{2} - 4)

x = - 2, x = 0, x = 2

Solution steps

x^{2} (x^{2} - 4)

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 0, x = 2

Identify critical points not in

f (x)

domain

Domain of

x^{2} (x^{2} - 4) : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 0, x = 2

\frac{x - 1}{x ^{2} + 1}

- \frac{4}{3}

y = - 3 x - 4

y = - sin (2 x)

tan (2 x - 5)

What is the critical f(x)=x^2(x^2-4) ?
The critical f(x)=x^2(x^2-4) is x=-sqrt(2),x=0,x=sqrt(2)