What is the domain of f(x)=\sqrt[3]{x-12} ?

The domain of f(x)=\sqrt[3]{x-12} is -infinity <x<infinity

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domain of f(x)=\sqrt[3]{x-12}

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

2 x + y = 6

f (x) = 4 x^{2} - x - 3

2 x - 12

(\frac{4}{5}, \frac{1}{10}), (\frac{1}{5}, \frac{15}{10})

- x + 4 - 1

What is the domain of f(x)=\sqrt[3]{x-12} ?
The domain of f(x)=\sqrt[3]{x-12} is -infinity <x<infinity