What is the inverse of f(x)=log_{6}(4x)+log_{6}(3) ?

The inverse of f(x)=log_{6}(4x)+log_{6}(3) is 2^{x-2}*3^{-1+x}

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inverse of f(x)=log_{6}(4x)+log_{6}(3)

inverse

f (x) = lo g_{6} (4 x) + lo g_{6} (3)

2^{x - 2} \cdot 3^{- 1 + x}

Solution steps

y = lo g_{6} (4 x) + lo g_{6} (3)

Replace

x

with

y

x = lo g_{6} (4 y) + lo g_{6} (3)

Solve for

y, x = lo g_{6} (4 y) + lo g_{6} (3)

2^{x - 2} \cdot 3^{- 1 + x}

f (x) = \frac{x ^{5}}{5}

f (x) = \frac{3 + x}{2 - x}

f (x) = \frac{x + 1}{x ^{2} - 6 x + 8}

f (x) = 2 x^{3} - 3 x^{2} + 7 x - 8

f (x) = ln (2 + ln (x))

What is the inverse of f(x)=log_{6}(4x)+log_{6}(3) ?
The inverse of f(x)=log_{6}(4x)+log_{6}(3) is 2^{x-2}*3^{-1+x}