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Popular >

midpoint (6,-9),(5,-4)

Solution

midpoint

(6, - 9), (5, - 4)

Solution

(\frac{11}{2}, - \frac{13}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (6, - 9), (x_{2}, y_{2}) = (5, - 4)

= (\frac{5 + 6}{2}, \frac{- 4 - 9}{2})

Refine

= (\frac{11}{2}, - \frac{13}{2})

Popular Examples

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f (x) = \frac{2 x + 1}{x - 1}

domain of f(x)=(x^2-1)^2-1 domain

f (x) = (x^{2} - 1)^{2} - 1

f (x) = \frac{1}{2} x^{2}

simplify (7.2)(9.16)simplify

(7.2) (9.16)

extreme f(x)=3x^5-5x^3 extreme points

f (x) = 3 x^{5} - 5 x^{3}

Frequently Asked Questions (FAQ)

What is the midpoint (6,-9),(5,-4) ?
The midpoint (6,-9),(5,-4) is (11/2 ,-13/2)