What is the perpendicular 2x+3y=-18 ?

The perpendicular 2x+3y=-18 is y= 3/2 x+b

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perpendicular 2x+3y=-18

perpendicular

2 x + 3 y = - 18

y = \frac{3}{2} x + b

Solution steps

Find the slope of

2 x + 3 y = - 18 : m = - \frac{2}{3}

Compute the slope of the perpendicular line:

m_{p} = \frac{3}{2}

Line with slope m=

\frac{3}{2} : y = \frac{3}{2} x + b

y = \frac{3}{2} x + b

x - 5 y = - 6, (0, 4)

(3, 3), (- 3, - 1)

f (x) = 4 tan (\frac{4 π}{3} x)

- 6 lo g_{2} (x)

f (x) = \frac{x ^{3}}{x ^{2} - 9}