What is the domain of f(x)= 1/(3-sqrt(25-x^2)) ?

The domain of f(x)= 1/(3-sqrt(25-x^2)) is -5<= x<-4\lor-4<x<4\lor 4<x<= 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 1/(3-sqrt(25-x^2))

domain

f (x) = \frac{1}{3 - 25 - x ^{2}}

- 5 \leq x < - 4 or - 4 < x < 4 or 4 < x \leq 5

Interval Notation

[- 5, - 4) \cup (- 4, 4) \cup (4, 5]

Solution steps

Find non-negative values for radicals:

- 5 \leq x \leq 5

Find undefined (singularity) points:

x = 4, x = - 4

Combine real regions and undefined points for final function domain

- 5 \leq x < - 4 or - 4 < x < 4 or 4 < x \leq 5

y = - 4 x - 3

\frac{3 x - 12}{x ^{2} - 8 x + 16}

f (x) = 3^{x} - 2

\frac{5}{x}

(x^{2} + 5) (8 - x) = 0

What is the domain of f(x)= 1/(3-sqrt(25-x^2)) ?
The domain of f(x)= 1/(3-sqrt(25-x^2)) is -5<= x<-4\lor-4<x<4\lor 4<x<= 5