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Popular >

extreme y=(2x-8)^{2/3}

Solution

extreme points

y = (2 x - 8)^{\frac{2}{3}}

Solution

Minimum (4, 0)

Solution steps

f^{'} (x) = \frac{4}{3 ( 2 x - 8 ) ^{\frac{1}{3}}}

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 4

into

(2 x - 8)^{\frac{2}{3}} : 0

Minimum (4, 0)

Popular Examples

domain of f(x)=-1/(sqrt(x+8))domain

f (x) = - \frac{1}{x + 8}

range of (x-3)^2+2 range

(x - 3)^{2} + 2

asymptotes of f(x)=(x^2)/(x-4)asymptotes

f (x) = \frac{x ^{2}}{x - 4}

domain of f(x)=((1-5t))/(6+t)domain

f (x) = \frac{( 1 - 5 t )}{6 + t}

inverse of f(x)=-2x^5-3 inverse

f (x) = - 2 x^{5} - 3

Frequently Asked Questions (FAQ)

What is the extreme y=(2x-8)^{2/3} ?
The extreme y=(2x-8)^{2/3} is Minimum(4,0)