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Popular >

distance (0,0),(-5,-5)

Solution

distance

(0, 0), (- 5, - 5)

Solution

52

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(0, 0)

and

(- 5, - 5)

is

= (- 5 - 0)^{2} + (- 5 - 0)^{2}

Simplify

= 52

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\frac{83.66}{88.29}

inverse of y=4^x inverse

y = 4^{x}

critical f(x)=x^3-x critical points

f (x) = x^{3} - x

range of 1/(4-x^2)range

\frac{1}{4 - x ^{2}}

domain of y=x^3-4x domain

y = x^{3} - 4 x

Frequently Asked Questions (FAQ)

What is the distance (0,0),(-5,-5) ?
The distance (0,0),(-5,-5) is 5sqrt(2)