What is the range of f(x)= 1/(x+2) ?

The range of f(x)= 1/(x+2) is f(x) 0

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range of f(x)= 1/(x+2)

range

f (x) = \frac{1}{x + 2}

f (x) < 0 or f (x) > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{1}{x + 2}

Inverse of

\frac{1}{x + 2} : \frac{1}{x} - 2

\frac{1}{x} - 2

Find the domain of each inverse function

Domain of

\frac{1}{x} - 2 : x < 0 or x > 0

Combine the intervals

f (x) < 0 or f (x) > 0

y = - (X - 3)^{2} + 1

f (x) = x^{\frac{3}{4}}

f (x) = x^{4} - 4 x^{3} + 4 x^{2}

f (x) = \frac{x}{x + 8}

f (x) = \frac{x + 2}{6 x ^{2} + x - 2}

What is the range of f(x)= 1/(x+2) ?
The range of f(x)= 1/(x+2) is f(x)<0\lor f(x)>0