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Popular >

distance (4,2),(8,5)

Solution

distance

(4, 2), (8, 5)

Solution

5

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(4, 2)

and

(8, 5)

is

= (8 - 4)^{2} + (5 - 2)^{2}

Simplify

= 5

Popular Examples

domain of f(x)=\sqrt[3]{t-1}domain

inverse of (x+3)/(x-5)inverse

\frac{x + 3}{x - 5}

inverse of f(x)=3+sqrt(x-4)inverse

f (x) = 3 + x - 4

inverse of f(x)=1-x^2 inverse

f (x) = 1 - x^{2}

domain of (2x^2-8x)/(x^2-7x+12)domain

\frac{2 x ^{2} - 8 x}{x ^{2} - 7 x + 12}

Frequently Asked Questions (FAQ)

What is the distance (4,2),(8,5) ?
The distance (4,2),(8,5) is 5