What is the domain of f(x)=sqrt(x^3-36x) ?

The domain of f(x)=sqrt(x^3-36x) is -6 = 6

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domain of f(x)=sqrt(x^3-36x)

domain

f (x) = x^{3} - 36 x

- 6 \leq x \leq 0 or x \geq 6

Interval Notation

[- 6, 0] \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

- 6 \leq x \leq 0 or x \geq 6

The function domain

- 6 \leq x \leq 0 or x \geq 6

f (x) = - 2 x - 4

\frac{8 x}{( 5 x ^{2} + 4 ) ^{2}}

f (x) = - \frac{1}{x - 3} + 2

f (x) = x^{3} - 3 x^{2} - 24 x - 4

(- 4, 5), (2, - 3)

What is the domain of f(x)=sqrt(x^3-36x) ?
The domain of f(x)=sqrt(x^3-36x) is -6<= x<= 0\lor x>= 6