What is the inverse of 1/(4(\frac{(1-x)){x})+1} ?

The inverse of 1/(4(\frac{(1-x)){x})+1} is (4x)/(3x+1)

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inverse of 1/(4(\frac{(1-x)){x})+1}

inverse

\frac{1}{4 ( \frac{( 1 - x )}{x} ) + 1}

\frac{4 x}{3 x + 1}

Solution steps

y = \frac{1}{4 \cdot \frac{1 - x}{x} + 1}

Replace

x

with

y

x = \frac{1}{4 \cdot \frac{1 - y}{y} + 1}

Solve for

y, x = \frac{1}{4 \frac{1 - y}{y} + 1}

\frac{4 x}{3 x + 1}

x - 1

\frac{2 x ^{2} - 5 x - 2}{x - 2}

f (x) = \frac{x ^{3} + 3 x ^{2}}{x ^{2} - 7 x + 12}

f (x) = \frac{6}{1 - e ^{x}}

y = x^{2} + 2 x + 1

What is the inverse of 1/(4(\frac{(1-x)){x})+1} ?
The inverse of 1/(4(\frac{(1-x)){x})+1} is (4x)/(3x+1)