What is the asymptotes of f(x)=((x^2+1))/(x-1) ?

The asymptotes of f(x)=((x^2+1))/(x-1) is Vertical: x=1,Slant: y=x+1

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asymptotes of f(x)=((x^2+1))/(x-1)

asymptotes

f (x) = \frac{( x ^{2} + 1 )}{x - 1}

Vertical : x = 1, Slant : y = x + 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{x - 1} : x = 1

Horizontal Asymptotes of

\frac{x ^{2} + 1}{x - 1} :

None

Slant Asymptotes of

\frac{x ^{2} + 1}{x - 1} : y = x + 1

Vertical : x = 1, Slant : y = x + 1

y + 4 x = 2

f (x) = 2 x^{2} + 9 x

f (x) = \frac{1}{x - 3}

f (1) = \frac{x ^{2} - 1}{x - 1}

f (x) = \frac{- 8}{x + 7}

What is the asymptotes of f(x)=((x^2+1))/(x-1) ?
The asymptotes of f(x)=((x^2+1))/(x-1) is Vertical: x=1,Slant: y=x+1