What is the inverse of f(x)=(x-1)^2-5 ?

The inverse of f(x)=(x-1)^2-5 is sqrt(x+5)+1,-sqrt(x+5)+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(x-1)^2-5

inverse

f (x) = (x - 1)^{2} - 5

x + 5 + 1, - x + 5 + 1

Solution steps

y = (x - 1)^{2} - 5

Replace

x

with

y

x = (y - 1)^{2} - 5

Solve for

y, x = (y - 1)^{2} - 5

x + 5 + 1, - x + 5 + 1

\frac{4}{9 + x}

\frac{3 x ^{2} - 18 x + 24}{x ^{2} - 4 x}

f (x) = 4 cos (x - \frac{π}{3}) + 2

\frac{x + 3}{x ^{2} - 4}

f (x) = x^{2} - 3 x - 4

What is the inverse of f(x)=(x-1)^2-5 ?
The inverse of f(x)=(x-1)^2-5 is sqrt(x+5)+1,-sqrt(x+5)+1