What is the domain of f(x)= 1/(sqrt(x^2-3x-4)) ?

The domain of f(x)= 1/(sqrt(x^2-3x-4)) is x 4

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domain of f(x)= 1/(sqrt(x^2-3x-4))

domain

f (x) = \frac{1}{x ^{2} - 3 x - 4}

x < - 1 or x > 4

Interval Notation

(- \infty, - 1) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 4

Find undefined (singularity) points:

x = 4, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 4

f (x) = \frac{3 x}{x + 5}

f (x) = 121 - x^{2}

y = x + 1

f (x) = \frac{x ^{2} + 7 x + 10}{x ^{2} - 25}

What is the domain of f(x)= 1/(sqrt(x^2-3x-4)) ?
The domain of f(x)= 1/(sqrt(x^2-3x-4)) is x<-1\lor x>4