What is the inverse of (3x+4)/(x^2-25) ?

The inverse of (3x+4)/(x^2-25) is (3+sqrt(9-4x(-25x-4)))/(2x),(3-sqrt(9-4x(-25x-4)))/(2x)

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inverse of (3x+4)/(x^2-25)

inverse

\frac{3 x + 4}{x ^{2} - 25}

\frac{3 + 9 - 4 x ( - 25 x - 4 )}{2 x}, \frac{3 - 9 - 4 x ( - 25 x - 4 )}{2 x}

Solution steps

y = \frac{3 x + 4}{x ^{2} - 25}

Replace

x

with

y

x = \frac{3 y + 4}{y ^{2} - 25}

Solve for

y, x = \frac{3 y + 4}{y ^{2} - 25}

\frac{3 + 9 - 4 x ( - 25 x - 4 )}{2 x}, \frac{3 - 9 - 4 x ( - 25 x - 4 )}{2 x}

f (x) = \frac{x + 11}{x ^{2} + 49 x}

5 x + 8 y = 4 y - 5

g (x) = - x + 1

f (x) = \frac{x + 6}{x - 7}

What is the inverse of (3x+4)/(x^2-25) ?
The inverse of (3x+4)/(x^2-25) is (3+sqrt(9-4x(-25x-4)))/(2x),(3-sqrt(9-4x(-25x-4)))/(2x)