What is the domain of f(x)=(3-x)/(x+1)-4/(5x-3) ?

The domain of f(x)=(3-x)/(x+1)-4/(5x-3) is x 3/5

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domain of f(x)=(3-x)/(x+1)-4/(5x-3)

domain

f (x) = \frac{3 - x}{x + 1} - \frac{4}{5 x - 3}

x < - 1 or - 1 < x < \frac{3}{5} or x > \frac{3}{5}

Interval Notation

(- \infty, - 1) \cup (- 1, \frac{3}{5}) \cup (\frac{3}{5}, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = \frac{3}{5}

The function domain

x < - 1 or - 1 < x < \frac{3}{5} or x > \frac{3}{5}

x^{4} + \frac{4}{3} x^{3} - 4 x^{2} - \frac{4}{3}

\frac{6 x}{1 - 7 x}

cos (2 x + 5)

y = 2 x + 1

f (x) = \frac{- 10}{10 - x}

What is the domain of f(x)=(3-x)/(x+1)-4/(5x-3) ?
The domain of f(x)=(3-x)/(x+1)-4/(5x-3) is x<-1\lor-1<x< 3/5 \lor x> 3/5