en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

midpoint (3,-4),(-1,10)

Solution

midpoint

(3, - 4), (- 1, 10)

Solution

(1, 3)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (3, - 4), (x_{2}, y_{2}) = (- 1, 10)

= (\frac{- 1 + 3}{2}, \frac{10 - 4}{2})

Refine

= (1, 3)

Popular Examples

inverse of y=ln(2x)inverse

y = ln (2 x)

intercepts of f(x)=6x-2y=12 intercepts

f (x) = 6 x - 2 y = 12

parity f(x)= 1/(x^2+1)parity

f (x) = \frac{1}{x ^{2} + 1}

extreme f(x)=x^2+12x+11 extreme points

f (x) = x^{2} + 12 x + 11

parity f(x)=-8x^7-x^5+2x^3 parity

f (x) = - 8 x^{7} - x^{5} + 2 x^{3}

Frequently Asked Questions (FAQ)

What is the midpoint (3,-4),(-1,10) ?
The midpoint (3,-4),(-1,10) is (1,3)