What is the inverse of (x^2-16)/(4x^2) ?

The inverse of (x^2-16)/(4x^2) is sqrt(-(16)/(4x-1)),-sqrt(-(16)/(4x-1))

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inverse of (x^2-16)/(4x^2)

inverse

\frac{x ^{2} - 16}{4 x ^{2}}

- \frac{16}{4 x - 1}, - - \frac{16}{4 x - 1}

Solution steps

y = \frac{x ^{2} - 16}{4 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 16}{4 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 16}{4 y ^{2}}

- \frac{16}{4 x - 1}, - - \frac{16}{4 x - 1}

x^{3} + x^{2} - 4 x - 4

f (x) = x^{2} + 2 x

y - 5 = - 2 (x + 5)

(\frac{2}{3})^{x} + 2

y = - 10 x - 3

What is the inverse of (x^2-16)/(4x^2) ?
The inverse of (x^2-16)/(4x^2) is sqrt(-(16)/(4x-1)),-sqrt(-(16)/(4x-1))