What is the domain of cot(1/8 x) ?

The domain of cot(1/8 x) is 8pin<x<8pi+8pin

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domain of cot(1/8 x)

domain

cot (\frac{1}{8} x)

8 πn < x < 8 π + 8 πn

Interval Notation

(8 πn, 8 π + 8 πn)

Solution steps

Take the denominator(s) of

cot (\frac{1}{8} x)

and compare to zero:

x = 8 πn

Periodicity of

cot (\frac{1}{8} x) : 8 π

Combine period:

8 πn \leq x < 8 π + 8 πn

and undefined points.

The domain is

8 πn < x < 8 π + 8 πn

f (x) = x^{4} - 12 x^{3}

(1, 3), (- 8, - 6)

\frac{x ^{2} - 4}{x ^{2}}

\frac{( 5 x + 4 ) ( 4 x - 2 )}{( x ^{2} - 36 ) ^{2}}

2 x + \frac{2}{3} y = 10