Solution
midpoint
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parity f(x)=-5x^3parity line m= 13/20 ,(20,9)line inverse of f(x)=2\sqrt[3]{x-3}inverse domain of f(x)= 1/(2x+3)domain periodicity of f(x)=tan(4x-pi)+1periodicity
Frequently Asked Questions (FAQ)
What is the midpoint (-1,4),(5,-6) ?
The midpoint (-1,4),(5,-6) is (2,-1)