What is the inverse of f(x)=((x+1))/(x+9) ?

The inverse of f(x)=((x+1))/(x+9) is (1-9x)/(x-1)

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inverse of f(x)=((x+1))/(x+9)

inverse

f (x) = \frac{( x + 1 )}{x + 9}

\frac{1 - 9 x}{x - 1}

Solution steps

y = \frac{x + 1}{x + 9}

Replace

x

with

y

x = \frac{y + 1}{y + 9}

Solve for

y, x = \frac{y + 1}{y + 9}

\frac{1 - 9 x}{x - 1}

\frac{2 x + 1}{x ^{2} + x - 30}

g (x) = 4 x + 6

\frac{x}{x ^{2} + 2 x + 3}

f (x) = 10 - 3 - x

(x + 3)

What is the inverse of f(x)=((x+1))/(x+9) ?
The inverse of f(x)=((x+1))/(x+9) is (1-9x)/(x-1)