extreme y=x^3+3x^2+3x+2

解答

极值点

y = x^{3} + 3 x^{2} + 3 x + 2

鞍点 (- 1, 1)

求解步骤

f^{'} (x) = 3 x^{2} + 6 x + 3

Find intervals:

递增

: - \infty < x < - 1,

递增

: - 1 < x < \infty

将

x = - 1

代入

x^{3} + 3 x^{2} + 3 x + 2 : 1

鞍点 (- 1, 1)

cr i t i c a l 2 cos (x) + sin (2 x)

cr i t i c a l f (x) = 3 x

d o main f (x) = sin (4 sin (4 x))

d o main f (x) = 2 x^{2} + x + 1

r an g e f (x) = (x - 3)^{2} + 1