What is the range of f(x)=(x^2-4)/(x-2) ?

The range of f(x)=(x^2-4)/(x-2) is f(x) 4

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range of f(x)=(x^2-4)/(x-2)

range

f (x) = \frac{x ^{2} - 4}{x - 2}

f (x) < 4 or f (x) > 4

Interval Notation

(- \infty, 4) \cup (4, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{x ^{2} - 4}{x - 2} : x < 2 or x > 2

Simplify

\frac{x ^{2} - 4}{x - 2} : x + 2

Extreme Points of

x + 2 :

None

Find the range for the interval

- \infty < x < 2 : - \infty < f (x) < 4

Find the range for the interval

2 < x < \infty : 4 < f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) < 4 or f (x) > 4

f (x) < 4 or f (x) > 4

f (x) = \frac{10}{x}

1 - \frac{x + 2}{x - 3}

f (x) = 0. 3^{x}

f (x) = \frac{1}{36 - t}

\frac{t}{∣ t ∣}

What is the range of f(x)=(x^2-4)/(x-2) ?
The range of f(x)=(x^2-4)/(x-2) is f(x)<4\lor f(x)>4