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Popular >

distance (-8,0),(1,4)

Solution

distance

(- 8, 0), (1, 4)

Solution

97

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 8, 0)

and

(1, 4)

is

= (1 - (- 8))^{2} + (4 - 0)^{2}

Simplify

= 97

Popular Examples

inverse of f(x)=log_{5}(2x-1)inverse

f (x) = lo g_{5} (2 x - 1)

periodicity of f(x)=tan(x+pi/2)periodicity

f (x) = tan (x + \frac{π}{2})

domain of f(x)=(sqrt(9+x))/(2-x)domain

f (x) = \frac{9 + x}{2 - x}

periodicity of f(x)=5tan(x+pi/2)periodicity

f (x) = 5 tan (x + \frac{π}{2})

inflection x/(5+x^2)inflection points

\frac{x}{5 + x ^{2}}

Frequently Asked Questions (FAQ)

What is the distance (-8,0),(1,4) ?
The distance (-8,0),(1,4) is square root of 97