What is the perpendicular y= 3/4 x+3,(4,1) ?

The perpendicular y= 3/4 x+3,(4,1) is y=-4/3 x+19/3

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perpendicular y= 3/4 x+3,(4,1)

perpendicular

y = \frac{3}{4} x + 3, (4, 1)

y = - \frac{4}{3} x + \frac{19}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{3}{4} x + 3

that passes through

(4, 1)

Find the slope of

y = \frac{3}{4} x + 3 : m = \frac{3}{4}

Compute the slope of the perpendicular line:

m_{p} = - \frac{4}{3}

Find the line with slope m=

- \frac{4}{3}

and passing through

(4, 1) : y = - \frac{4}{3} x + \frac{19}{3}

y = - \frac{4}{3} x + \frac{19}{3}

y = x^{2} - 4

sin (2 x)

\frac{8 ( \frac{6}{5 x - 4} ) + 4}{x - 4}

11

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What is the perpendicular y= 3/4 x+3,(4,1) ?
The perpendicular y= 3/4 x+3,(4,1) is y=-4/3 x+19/3