What is the domain of y=sqrt(x^2+4) ?

The domain of y=sqrt(x^2+4) is -infinity <x<infinity

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domain of y=sqrt(x^2+4)

domain

y = x^{2} + 4

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = x^{2} - x - 2

f (x) = 2 x^{2} + 8 x - 3

f (x) = (x + \frac{1}{x}) + \frac{1}{( x + \frac{1}{x} )}

g (x) = x + 4

f (x) = x^{3} - x^{2} - x - 2

What is the domain of y=sqrt(x^2+4) ?
The domain of y=sqrt(x^2+4) is -infinity <x<infinity